求证:CD:BC=DF:BF
AB=CD,AE垂直BC,DF垂直BC,CE=BF,求证AE=DF
如图,AB=CD,AE⊥BC,DF⊥BC,CE=BF.求证:AE=DF.
已知:如图,AD=BC,AB=CD,DE=BF求证:BE=DF
已知如图,AB+AD=BC+CD,求证BF+DF=BE+DE
11.214页练习的第2题:AB=CD,AE垂直于BC,DF垂直于BF,CE=BF,求证AE=DF
在四边形ABCD中,已知AB=CD,AD=BC,DE=BF,求证BE=DF
在四边形ABCD中,已知AB=CD,AD=BC,DE=BF.求证BE=DF
如图,已知,AB=CD,AE⊥BC于E点,DF⊥BC于F,AE=DF,求证CE=BF
如图,AB=CD,AE⊥BC,DF⊥BC,垂足分别为E,F,CE=BF.求证AE=DF
如图,AB=CD,AE⊥BC,DF⊥BC,垂足分别为E,F.CE=BF,求证AB‖CD.
如图,AB=CD,AE⊥BC,DF⊥BC,垂足分别为E,F,CE=BF,求证:AB∥CD.
如图,在梯形ABCD中,AB//CD,AD=BC,点E,F在AB上,且AE=BF,连接CE,DF.求证:CE=DF .