CaCO3(s)==CaO(s)+CO2(g) ΔH=+178.5 KJ·mol-1 的意义是
CaCO3(s)==CaO(s)+CO2(g) ΔH=+178.5 KJ·mol-1 的意义是
已知CaCO3(s)=CaO(s)+CO2(g);ΔH=+175.7kj/mol C(s)+O2(g)=CO2(g);Δ
已知:C(s)+O2(g)=CO2(g) 变量H=-393.5kJ/mol,CaCO3(s)=CaO(s)+CO2(g)
已知:C(S)+O2(g)=CO2(g) △H=-393.5kj/mol CACO3(S)=CAO(S)+CO2(g)
已知热化学方程式CaCO3(S)=CaO(s)+CO2(g)-178.3kj,C(s)+O2(g)=CO2+395kj
计算反应CaCO3(s)=CaO(s)+CO2(g)
已知100kpa,298.15K时石灰石分解反应,caco3=cao+co2 H=-178.3kj/mol S=+160
C(s)+O2(g)=CO2(g) ΔH=-393.5 kJ/mol
已知下列数据:CaO(s)+SO3(g)=CaSO4(s) △H=-401.9KJ/mol 是通过计算说明能否用CaO吸
CaCO3(s)→CO2(g)+CaO(s)-157KJ;C(s)+O2(g)+393.5KJ
1.c(s)+o2(g)=co2(g);△H=-393.5kj/mol
2CO(g)+O2(g)=2CO2(g) ΔH=-566 kJ/mol Na2O2(s)+CO2(g)=Na2CO3(s