作业帮 > 数学 > 作业

化简(2cos(x/2)^2-sinx-1)/(根号2sin(π/4+X))

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/26 22:02:05
化简(2cos(x/2)^2-sinx-1)/(根号2sin(π/4+X))
[2cos(x/2)^2-sinx-1]/[√2sin(π/4+X)]
=[cosx+1-sinx-1]/[√2sin(π/4+X)]
=[cosx-sinx]/[√2sin(π/4+X)]
=√2[√2/2cosx-√2/2sinx]/[√2sin(π/4+X)]
=√2[cosπ/4cosx-sinπ/4sinx]/[√2sin(π/4+X)]
=√2[cos(π/4+x)]/[√2sin(π/4+X)]
=cos(π/4+x)/sin(π/4+X)
=cot(π/4+x)