(m²-2m)²n+2n(m²-2m)+n
化简m/(m+n)²+n/m²-n²-2n²/(m+n)(m²-n
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
【(m+n)(m-n)-(m-n²)+2n(m-n)】÷4n
(m²-2m)²n+2n(m²-2m)+n
(m+2n)²+2(m+n)(2m-n)+(2m+n)² 因式分解
m-n分之m - m+n分之n + m²-n²分之2mn
化简(m²/m-n - m+n)÷2m²-mn/n - m
证明(m+n)²/2+(m+n)/4≥(m√n)+(n√m)
计算m-n+[(2n²)/(m+n)]
因式分解:(m-n)²-(2n-m)²
(m+n)²+2(m+n)+1因式分解,
先化简再求值:(2m-n)(m+n)+(m-n)²-(6m³-4m²n)÷2m,其中m=2