7/x^2+x-6/x^2-1+3/x^2-x=0求方程解发
7/x^2+x-6/x^2-1+3/x^2-x=0求方程解发
解一道初一的分式方程(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
解方程(x+1/x+2)-(x+2/x+3)=(x+5/x+6)-(x+6/x+7)
解方程:x+2/x+1-x+3/x+2=x+6/x+5-x+7/x+6
解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3
x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值
解方程(x-2)/(x-3)-(x-3)/(x-4)=(x-5)/(x-6)-(x-6)/(x-7)
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
解方程:x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)