解一道初一的分式方程(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/03/29 22:49:18
解一道初一的分式方程
(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)
求x的值
(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)
求x的值
(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)
(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+6)
1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6)
1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6)
(x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6)
(2x+9)/(x+2)(x+7)=(2x+9)/(x+3)(x+6)
所以2x+9=0
x=-4.5
经检验,x=-4.5是原方程得解
(x+2-1)/(x+2)+(x+7-1)/(x+7)=(x+3-1)/(x+3)+(x+6-1)/(x+6)
1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6)
1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6)
(x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6)
(2x+9)/(x+2)(x+7)=(2x+9)/(x+3)(x+6)
所以2x+9=0
x=-4.5
经检验,x=-4.5是原方程得解
解一道初一的分式方程(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6)求x的
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程
解分式方程x/X-2-1-X^2/X^2-5X+6=2X/X-3
解分式方程:x-3/x-1-x-4/x-2=x-5/x-3-x-6
解分式方程,7/(x^2+x)+3/(x^2-x)=6/(x^2-1)
分式方程3/x+6/x-1=7/x^2-x的解为x=
解分式方程6x-1/3x+2=4x-7/2x-5
一道分式方程.X-2分之X-1减X-3分之X-2=X-5分之X-4减X-6分之X-5.
解分式方程x-2分之x=x-3分之2x+x的平方-5x+6分之1-x的平方
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)