x.y.z都大于0,xy+yz+xz=1,求1/(x+y)+1/(x+z)+1/(y+z)的最小值

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/12 19:02:51

将x y 设定为0:0.01:100（范围0-100,步长0.01）,用matlab算了一下,给出的最小结果是 0.044996,以下是Matlab程序,凑合着看看能用不.
for x = 0:0.01:100
for y = 0:0.01:100
z = (1-x.*y)./(x+y);
t = 1./(x+y) + 1./(x+z)+1./(y+z);
end
end
min(t)

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