根号2sinπ/32*cosπ/32*cosπ/16*cosπ/18 怎么化简
根号2sinπ/32*cosπ/32*cosπ/16*cosπ/18 怎么化简
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
cos(π/32)*cos(π/16)*cos(π/8)=
cos sin π √
高中三角函数化简求值化简:√2-sin^2+cos4 (根号下) cos(π/9)*cos(2π/9)*cos(3π/9
cos(α+π/4)为什么等于根号2/2cosα-根号2/2sinα?
(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
已知cos(π\3-2)=1\3,则cosα+根号3sinα=
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
根号[1-2sin(3-π)cos(3-π)]化简