(1-2除以x)除以x的平方-4x 4除以x的平方-4-(x 4除以x 2)

(8x+9)/(x^2+x-6)=a/(x+3)+b/(x-2)8x+9=a(x-2)+b(x+3)8x+9=(a+b)x+(3b-2a)建立方程组a+b=83b-2a=9得到解a=3b=5

((x+2)/(x^2-2x)-(x-1)/(x^2-4x+4))/((x^2-16)/(x^2+4x))=((x+2)(x-2)-(x-1)x)/((x-2)^2*x)/((x-4)/x)=((x-

4x三次除以(-2x)平方-(2x平方-x)除以(1/2x)=4x^3/4x^2-(2x^2-x)/(1/2x)=x-2x(2x-1)/x=x-2(2x-1)=x-4x+2=-3x+2

/>分式有意义,x-1≠0x≠1x+|(1+x²-2x)/(x-1)|=x+|(x-1)²/(x-1)|=x+|x-1|x>1时,原式=x+x-1=2x-1x

1除以(x的平方+3x+2)+1除以(x平方+5x+6)+1除以(x平方+7x+12)=1/（x+1）（x+2）+1/(x+2)(x+3)+1/(x+3)(x+4)=1/(x+1)-1/(x+2)+1

x²-5x+1=0x²+1=5x两边除以xx+1/x=5x+1/x=5两边平方x²+2+1/x²=25x²+1/x²=23

[x的平方-x分之x+1-x的平方-2x+1分之x]除以x分之1=[(x+1)/x(x-1)-x/(x-1)²]×x=(x+1)/(x-1)-x²/(x-1)²=(x&#

题目是（5x+2)/(x²+x)=3/(x+1)这样吧?∵（x+1）作分母,不为0,可直接约分∴（5x+2)/x=3∴5x+2=3x∴2x=-2∴x=-1

先说答案x1=2x2=1/22(x*2+1/x*2)-3(x+1/x)-1=02(x+1/x)*2-4-3(x+1/x)-1=0(x+1/x)*2-3/2(x+1/x)-5/2=0(x+1/x-3/4

[x-1]/(x-3)=m^2/(2x-6)2(x-1)=m^2当X-3=0,即X=3时方程有增根,代入得：m^2=2(3-1)=4m=+2或-2

(x+1)/x^2-2x^2/(x+1)=1令a=(x+1)/x^2,则x^2/(x+1)=1/aa-2/a-1=0a^2-a-2=0(a-2)(a+1)=0a=2,a=-1a=2(x+1)/x^2=

x=(√20-4)/2=(2√5-4)/2=√5-2所以x²=(√5)²-4*√5+4=9-4√51/x=1/(√5-2)=(√5+2)/[(√5)²-2²]=

将3x/(x-1)-x/(x+1)通分得

(x²+xy)/(x+y)²=x(x+y)/(x+y)²=x/(x+y)2xy/(x+y)²x/(x²-y²)∵最简公分母为：(x+y)&#

椭圆X平方除以4+Y平方除以2=1用三角换元x=2cosay=根号2sinaY除以（X-4）=根号2sina除以（2cosa-4）下面看这一部分2sina除以（2cosa-4）=（2sina-0）除以

x²/(x-1)-x=(x²-x²+x)/(x-1)=x/(x-1)

2/(x^2-1)-1/(x-1)=12/(x+1)(x-1)-1/(x-1)=1两边乘(x+1)(x-1)2-（x+1）=x^2-1x^2+x-2=0(x+2)(x-1)=0x1=-2x2=1(舍)

2x分之x的平方-4x+4除以x平方分之x的平方-2x+1等于2分之x,当x=0或2时,分式无意义

[(x²-4x+4)/(2x)]÷[(x²-2x+1)/x²]=[(x-2)²/(2x)]/[(x-1)²/x²]=(x-2)²x

y=(3x²+2x+2)/(x²+x+1)yx²+yx+y=3x²+2x+2(y-3)x²+(y-2)x+(y-2)=0x是实数,所以判别式大于等于0