x的平方加y的平方在复数范围内分解因式-搜答案-智慧作业帮

x^2+4|x|+3=0(|x|+3)(|x|+1)=0|x|=-3或|x|=-1x=±3i^2或x=±i^2

x^2+|x|=0|x|>=0,所以x^2

x^2-3=x^2-(√3)^2=(x+√3)(x-√3)

2x^2-1=2(x^2-1/2)=2(x+√2/2)(x-√2/2)

/>2x²+x+1=2[x²+(1/2)x]+1=2[x²+2×(1/4)x+(1/4)²]-1/8+1=2(x+1/4)²+7/8=2(4x+1)&

X的4次方减4X的平方加4=(x²-2)²=(x+√2)²(x-√2)²

解x²-5=x²-(√5)²=(x-√5)(x+√5)x²-4y²=x²-(2y)²=(x-2y)(x+2y)

x²-4xy+3y²-4x+10y+3=(x-y)(x-3y)-4x+10y+3=(x-y-3)(x-3y-1)x²+xy-2y²+2x+7x-3=(x+2y)

原式=2[x^2+1/2xy+(y/4)^2]-y^2-1/8*y^2=2(x+y/4)^2-9/8*y^2=[√2(x+y/4)+(√9/8)y]*[√2(x+y/4)-(√9/8)y]上式再化减一

x²=-3x=±√3i

原式=(√3x)²-(√2y)²=(√3x+√2y)(√3x-√2y)

1/25x^2-0.16y^2=1/25x^2-4/25y^2=1/25(x^2-4y^2)=1/25(X-2Y)(X+2Y)

原式=(2xy)²+xy+(1/4)²-17/16=(2xy+1/4)²-17/16=(2xy+1/4+√17/4)(2xy+1/4-√17/4)

(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!

1、x²-3x+2=(x-1)(x-2)2、原式=(3y-4)²3、原式=(x²-3)(x²+1)=(x+√3)(x-√3)(x²+1)

x^2+xy+y^2=0x/y=-1/2+√3/2i或-1/2-√3/2i对应：y/x=-1/2-√3/2i或-1/2+√3/2i原式=（-1/2-√3/2i）^998+(-1/2+√3/2i)^99

（1）x的平方+2x-4=(x+1)^2-5=(x+1+根号5）（x+1-根号5）(2)x的平方+xy-3y的平方=(x+y/2)^2-y^2/4-3y^2=(x+y/2)^2-13y^2/4=(x+

2x²+4x-3=2(x²+2x+1)-2-3=2(x+1)²-5=(√2x+√2+√5）（√2x+√2-√5）

3x^2－5y^2=(√3x+√5y)(√3x-√5y)