x平方-1分之x除以1减x加1分之x-搜答案-智慧作业帮

1楼最后算错了引用一下：1/(x+1)-1/(x²-1)÷(x+1)/(x²-2x+1)=1/(x+1)-1/(x+1)(x-1)×(x-1)(x-1)/(x+1)=1/(x+1)

原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1

(x+1)(x+2)/(x²+4x+4)×(3x+6)/(2x²-8)×6÷1/(x²-4)=(x+1)(x+2)/(x+2)²×2(x+2)/2(x+2)(x

[x/(x+3)+6x/(x+3)(x-3)]×(x+3)(x-3)=x(x-3)+6x=x-3x+6x=x+3x

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

化简结果x/(x+1)

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

(1-x)/(x+2)+(x²+2x+1)/2÷(x²-1)/x-1=(1-x)/(x+2)+(x+1)²×(x-1)/(x+1)(x-1)=(1-x)/(x+2)+(x

[(x+2)/(x-2)-(x-4)/(x^2-4x+4)]÷(x^2-1)/(x^2+x)=[(x^2-4)/(x-2)^2-(x-4)/(x-2)^2]*x(x+1)/(x-1)(x+1)=(x^

因为x^2-x^2/2=3==>x^2=6==>x=根号61/(1-x)-(1/(1x))/(x/(x^2-1)x)=1/(1-x)-(1/(1x))/((xx^3-x)/(x^2-1))=1/(1-

再问：呵呵你写错了再问：是2分之x

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

=[(x+1)(x-1)/(x-1)²-(x-1)/(x+1)]×(x-1)/x=[(x+1)²-(x-1)²]/(x+1)(x-1)×(x-1)/x=4x/(x+1)(

√x－1／√x＝3两边平方得出x＋1／x＝11(1+xˆ2)∕x=x＋1／x＝11

你可以手写照下来吗?看不懂再答：再问：再问：你能放大点吗再问：人呢再答：哦，我再写一遍再问：嗯再答：再问：图片好小再问：不过基本会了

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

x除以（x平方减x加1）=7两边取倒数得(x^2-1)/x=1/7即x-1/x=1/7两边同时平方得x^2+(1/x^2)-2=1/49即x^2+(1/x^2)=99/49令y=x平方除以（x的4次方

〔(x^2-4x+4)/(x^2-4)〕/〔(x^2-2x)/(x+2)〕-1/x+1=〔(x-2)^2/(x+2)(x-2)〕/〔x(x-2)/(x+2)〕-1/x+1=〔(x-2)/(x+2)〕/

x的平方-1分之x除以x的平方分之x的平方=x²-(x/1)/(x²/x²）=x²-(x)/1=x²-x