x²+6x+9分之x²-9×x²-3x分之3x³+9x²

若通分,则为{x(2x^2+12x+27)}/{9(x+3)}

请加括号再问：没有括号再答：是这样吗？x/(x-2)+x/(x-7)-9=x/(x-1)+1+x/(x-6)-8再问：是：x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(

x+3分之x+x平方-9分之6等于x-3分之1两边乘（x+3）（x-3）x(x-3)+6=x+3x²-3x+6=x+3x²-4x+3=0(x-3)(x-1)=0x1=3x2=1由于

(x-3)分之1+(6+2x)分之1-x-(x²-9)分之6=1/(x-3)+(1-x)/2(x+3)-6/(x+3)(x-3)=[2(x+3)+(1-x)(x-3)-12]/2(x+3)(

1/x（x+3)+1/（x+3)(x+6)+1/（x+6)(x+9）=3/2（x+9)（1/3）×[3/x（x+3)+3/（x+3)(x+6）+3/（x+6）（x+9)]=3/2（x+9）（1/3)[

希望能帮上忙,第一步x-7/x-9+x-3/x-5=x-4/x-6+x-6/x-8第二步(x-9)+2/x-9+(x-5)+2/x-5=(x-6)+2/x-6+(x-8)+2/x-8第三步1+2/x-

X的平方+3X分之X的平方+9X+X的平方+6X+9分之X的平方-9=x（x＋3）分之（x²＋9x）＋（x＋3）²分之（x＋3）（x-3）==x（x＋3）分之（x²＋9x

(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(

由(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)得：（X-4）/（X-5）-（X-7）/（X-8）=（X-5）/（X-6）-(X-8）/（X-9）即：【

因为(x-4)/(x-5)=[(x-5)+1]/(x-5)=1+1/(x-5)……所以原方程可化为1+1/(x-5)-1-1/(x-6)=1+1/(x-8)-1-1/(x-9)1/(x-5)-1/(x

x=123/14

公分母是2(x+3)²(x-3)所以6-2x分之x-1=2(x+3)²(x-3)分之[-2(x-1)(x+3)²]x²-9分之6=2(x+3)²(x-

因为(x-4)/(x-5)=[(x-5)+1]/(x-5)=1+1/(x-5)……所以原方程可化为1+1/(x-5)-1-1/(x-6)=1+1/(x-8)-1-1/(x-9)1/(x-5)-1/(x

(x-4）/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)对方程两边各自通分：[(x-4)(x-6)-(x-5)(x-5)]/[(x-5)/(x-6)]=[(x-7

2x分之(x+2)*(x^2+5x+6)分之(x^3-3x^2)÷(x^2+2x-3)分之(x^3-9x)=2x分之(x+2)*(x+2)(x+3)分之x^2(x-3)*x(x+3)(x-3)分之(x

每个分式减去1(x-4-x+5)/(x-5)+(x-8-x+9)/(x-9)=(x-7-x+8)/(x-8)+(x-5-x+6)/(x-6)1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6

x(x+3)分之1+(x+3)(x+6)分之1+(x+6)(x+9)分之1+(x+6)(x+9)分之1+...+(x+99)(x+102)分之1=1/3[x(x+3)分之3+(x+3)(x+6)分之3

(x+7)/(x+6)+(x+9)/(x+8)=(x+10)/(x+9)+(x+6)/(x+5)1+1/(x+6)+1+1/(x+8)=1+1/(1+9)+1+1/(x+5)1/(x+6)+1/(x+

注:分子/分母(1/x-3)+(1/9-x^2)-(x-1/6-2x)通分:=2(x+3)/2(x+3)(x-3)+12/2(9-x^2)-(x-1)(3+x)/2(3-x)(3+x)=2x+6/2(