x^4 (sin(3x))^2是x的几阶

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已知sin X+cos X=m,|m|小于等于根号2且|m|不等于1,求sin X^3+cos X^3,sin X^4+

sinx+cosx=m平方sin²x+cos²x+2sinxcosx=m²1+2sinxcosx=m²sinxcosx=(m²-1)/2所以sin&s

化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1

2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1=-(1-2sin^2[(π/4)+x)-√3cos2x=-cos(π/2+2x)-√3cos2x=sin2x-√3cos2x=2[

化简【完整步骤!】1.(sin^4x-sin^2x)/secx2.sin^4x-cos^4x【这道题的正确答案是sin^

1.(sin^4x-sin^2x)/secx=sin^2x(sin^2x-1)cosx=-sin^2xcos^2xcosx=-sin^2xcos^3x2.sin^4x-cos^4x=(sin^2x+c

已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)

2sin(x-π/4)sin(x+π/4)=cos(x-π/4-x-π/4)-cos(x-π/4+x+π/4)=-cos2xf(x)=cos(2x-π/3)-cos2x=cos(2x-π/6-π/6)

三角等式求证:cos^6x+sin^6x=1-3sin^2x+3sin^4x

用公式a³+b³=(a+b)(a²-ab+b²)cos^6x+sin^6x=(cos²x)³+(sin²x)³=(cos

求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x).

f(x)=cos(3x)*cos(2x)+sin(3x)*sin(2x)=cos(3x-2x)=cosxf'(x)=-sinx

(急)数学化简题根号3 sin x+cos x1-2sin2 x+sin x cos x注:sin2 x是sin平方x

1.√3sinx+cosx=2*(sinx*√3/2+cosx/2)=2(sinxcosπ/6+cosxsinπ/6)=2sin(x+π/6)2.用万能公式可得字数受限

s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)

x=0:0.1:2*pi;s=2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x);plot(x,s)

已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,

f(x)=sin(2x-π/6)=cos[π/2-(2x-π/6)]=cos(2π/3-2x)=cos(2x-2π/3),故f(x)为偶函数,且其关于x=π/3对称,周期为π,因此a的最小整数为π.

证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+

sinx+siny+sinz-sin(x+y+z)=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]sinx+siny+sinz-sin(x+y+z)=2sin[(x+y)/

已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x

f(x)=sin^2x+2√3sinxcosx+sin(x+π/4)sin(x-π/4)=(1-cos2x)/2+√3sin2x+(1/2)2sin(x-π/4)cos(x-π/4)=2-2cos2x

三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)

sin(x-900°)cos(-90°-x)cos(1440°-x)/sin(x-270°)sin(-x-720°)=sin(-180°+x)cos(-90°-x)cos(-x)/sin(-270°+

化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x

sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x

1/sin^2x的不定积分谢谢!(是1/sin x * sin x)

解sin^2x=1/csc^2x∫csc^2xdx=-cotx+c不懂追问再问:为什么是-cot不是cot呢?再答:cot'=-csc^2x这里是正的

1.已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4).注:π是pai.

1.已知函数f(x)=cos(2x-π/3)2sin(x-π/4)sin(xπ/4)(1)求函数f(x)的最小正周期和图像的对称轴方程(2)求函数f(x)在区间[-π/12,π/2]上的值域⑴f(x)

sin(5x)-sin(3x)= 根号2cos(4x)

1、sinx=2分之根号2,或者cos(4x)=02、sinx=负二分之一,或者cosx=二分之一,或者cosx=0

证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4

sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=sin^2(x)+cos(x+30)[cos(x+30)+sinx]=sin^2(x)+cos(x+30)(cosxcos30

(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x

sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x