s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)
s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x)
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
在mathematica里输入Plot[Sin[x] Sin[x + 2] - Sin[x + 1]Sin[x + 1]
已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)
三角等式求证:cos^6x+sin^6x=1-3sin^2x+3sin^4x
sin(5x)-sin(3x)= 根号2cos(4x)
已知Sin(2x+pi/3)=1/3,求Sin(5Pi/6-4x),
3道求极限的题目1.sin 2x/sin 5x (x→0)2.(sin x - sin a)/(x - a) (x→a)
-sin(3x/2)*sin(x/2)等于什么为什么
解方程 sin^2*(3x)+sin^5*(5)x+sin^2*(7x)+sin^2*(9x)=2
x*(1+sin^2 x )/sin^2x 不定积分