x-2分之A (x-2)分之B=(X-2)2

右边=[a(2x-3)+b(x+2)]/(x+2)(2x-3)=(2a+b)x+(2b-3a)]/(x+2)(2x-3)=(5x-11)/(x+2)(2x-3)所以(2a+b)x+(2b-3a)=5x

A=3,B=-1.原式可以化成2x+5=A(x+2)+B(x+1),即A+B=2,2A+B=5,解得A=3,B=-1

你的题目应该是：2x/(x^2-1)=A/(x+1)+B/(x-1)对问题进行变形得：2x/[(x+1)(x-1)]=A/(x+1)+B/(x-1)对等式的右边进行通分整理得2x/[(x+1)(x-1

(x-1)(x-2)分之2x+1=x-1分之A+x-2分之B两边乘（x-1）(x-2)2x+1=A(x-2)+B(x-1)2x+1=(A+B)X-(2A+B)A+B=22A+B=-1两式相减A=-1-

先回答第一个：讲后面的式子先通分,然后分母就变成了（x-1）（x+2）,分子就变成A（x+2）+B（x-1）,化简一下等于（A+B)x+2A-B,因为左右两边是自要相等,所以有A+B=2,2A-B=-

右边通分=[A(x-2)-B]/(x-2)²=[Ax+(-2A-B)]/(x-2)²=(x+3)/(x-2)²所以Ax+(-2A-B)=x+3A=1-2A-B=3所以A=

(b+x)/a+2=(x-a)/b两边乘abb²+bx+2ab=ax-a²(a-b)x=a²+2ab+b²=(a+b)²a≠b则a-b≠0所以x=(a

把右边的式子通分再合并得2A+B=52B-3A=-11A=3B=-1

由于A/(X+6)+B/(X-3)=(AX-3A+BX+6B)/(X+6)(X-3)=(2X+1)/(x+6)(x-3)所以,A+B=2,6B-3A=1,解得,A=11/9B=7/9

(2x-3)/(x^2-x)=(2x-3)/x(x-1)A/(x-1)+B/x=(Ax+Bx-B)/x(x-1)=[(A+B)x-B]/x(x-1)两式对比A+B=2B=3A=2-B=-1所以A+B=

x-1分之A+x分之B=x^2-x分之Ax+x^2-x分之B(x-1)=x^2-x分之(A+B)x-B因此A+B=2B=3所以A=-1,B=3A-B=-4

右边通分：A/(X+1)+B/X=［AX+B(X+1)］/X(X+1)=［(A+B)X+B］/(X^2+X)与左边比较得方程组：A+B=2B=3解得：A=-1,B=3.∴A-B=-1-3=-4.

右边通分=[a(x+2)-b(x-3)]/(x-3)(x+2)=[(a-b)x+(2a+3b)]/(x-3)(x+2)=(2x+7)/(x-3)(x+2)所以(a-b)x+(2a+3b)=2x+7所以

向量a乘以向量b=cos(3x/2)乘以cos(x/2)-sin(3x/2)乘以sin(x/2)=cos(3x/2+x/2)(余弦函数两角和公式）=cos2x因为x属于（0,π/2),则2x属于（0,

a=(cos3x/2,sin3x/2),b=(cosx/2,-sinx/2),(1)a*b=(cos3x/2,sin3x/2)*(cosx/2,-sinx/2)=cos(3x/2)*cos(x/2)-

右边=[a(x-1)-b(3x+2)]/(x-1)(3x+2)=[(a-3b)x+(-a-2b)]/(3x²-x-2)=(4x-9)/(3x²-x-2)所以(a-3b)x+(-a-

(x+3)/(x-2)²≡A/(x-2)+B/(x-2)²,部分分式(x+3)/(x-2)²=[A(x-2)+B]/(x-2)²x+3=A(x-2)+B当x=2

再问：求求大神能把方程左边写一下吗，求再答：

A/(x+1)+B/(x-1)=(2x+3)/(x²-1)[(x-1)A+(x+1)B]/(x²-1)=(2x+3)/(x²-1)[Ax-A+Bx+B]/(x²

x分之x+3=3分之13x+9=x2x=-9x=-9/2a-b分之1-a+b分之1+a的平方+b的平方分之2b=(a+b)/(a+b)(a-b)-(a-b)/(a+b)(a-b)+2b/(a²