153 (10 x)-(10 x)=153

等于37因为：【】都是一样的数字的话那他们就可以合并同类项：[]{10+1}*5=1980所以算出为37~

1/[x(x-1)]=1/(X-1)-1/X1/[x(x+1)]=1/X-1/(X+1)1/(X-1)-1/X+1/X-1/(X+1)+...+1/(X+9)-1/(X+10)=1/(x+10)1/(

x+2x×10=10x+2x+36x+20x=12x+3621x-12x=369x=36x=4

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

 再问：额、不懂再答： 再答：后面的看做一个整体再问：好的吧、谢谢大神再答：回来的话，请采纳再问：啊、突然明白了呢。。。

(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(x+

(9X+8)(-9X+80)=1855-81X^2+648X+640-1855=0X^2-8X+15=0X=3或5

1.(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

X(1+2+3+4+5+6+7+8+9+10+11)=1980,X66=1980等于30

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

1/x(x+1)+1/(x+1)(x+2)+...+1/(x+9)(x+10)=1/(x+10),1/x(x+1)+1/(x+1)(x+2)+...+1/(x+9)(x+10)=1/x-1/(x+1)

你看看,怎么样：#include"Stdio.h"intmain(void){inti=1;floatx,y=1.0;floatsum=0.0;scanf("%f",&x);while(y>1e-4)

同时乘6060×（x/15+x/12+x/10）=1365×604x+5x+6x=8190015x=81900x=81900÷15x=5460很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选

(1)(X+7)/(X+6)+(X+9)/(X+8)=(X+10)/(X+9)+(X+6)/(X+5)这类方程重在运算的技巧性,观察分母7+9=10+6;6+8=5+9所以先移项:(X+7)/(X+6

就是当x!=0时进入循环

(x-10+2)/(x-10)+(x-6+2)/(x-6)=(x-7+2)/(x-7)+(x-9+2)/(x-9)1+2/(x-10)+1+2/(x-6)=1+2/(x-7)+1+2/(x-9)1/(

9x=59.94x=59.94/9=6.66

三分之一X+四分之一X+三分之一X-10=X12/4x+12/3x+10/4x-10=x12/11x-10=x12/11x-x=1012/1x=-10x=-120

=x^2+10x-24+x^2+15x+56-x^2+5x+50=x^2+30x+82=4+60+82=146其实,不化简,直接代入=14*0+9*10+7*8=0+90+56=146也很简单