1/[x(x-1)]+1/[x(x+1)]+…+1/[(x+9)(x+10)]=1/(x+10)
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-1
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
1/[x(x-1)]+1/[x(x+1)]+…+1/[(x+9)(x+10)]=1/(x+10)
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
x+x^2+x^3+…+x^9+x^10=a0+a1(1+x)+a2(1+x)^2+…a9(1+x)9+a10(1+x)
如果3x*x-x=1那么9x*x*x*x+12x*x*x-3x*x-7x+2001等于多少
1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980
1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
X+7/X+1+X+8/X+2-X+9/X+3-X+10/X+4 的解法