X/15 + X/12 + X/10 = 1365,求X,
X/15 + X/12 + X/10 = 1365,求X,
已知x/15+x/12+x/10=1365,求x
已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值
方程式求计算过程X/15+X/12+X/10=1365
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
已知x -2x=5,求代数式x四次方+3x³-12x² -31x-15
x+x=x+15
(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x
3^x=2^x,求x.5^(x-1)·10^3x=8^x求x
(X+X)+(X-X)+(X*X)+(X/X)=100