sin除3根号1 2cosx第一类换元求不定积分
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sin^3X+cos^3X=(sinx+cosx)(sin^2x-sinxcosx+cos^2x)=根号2(1+sinxcosx)sinX+cosX=根号2所以sin^2x+cos^2x+2sinxc
2sin(X+π/3)=2(sinxcosπ/3+cosxsinπ/3)=2(1/2*sinx+二分之根号3*cosx)=Sinx+(根号3)*Cosx
定义域需满足:sinx-√3/2>=0,即sinx>=√3/2,得:2kπ+π/3=
因为:函数f(x)=2cosx·sin(x+π/3)-√3(sinx)^2+sinx·cosx=2cosx·sin(x+∏/3)-√3(sinx)^2+sinx·cosx=2cosx·sinx·cos
f(x)=2cosx*sin(x+π/3)-√3sinx^2+sinx*cosx=2cosx*(sinxcosπ/3+cosxsinπ/3))-√3sinx^2+sinx*cosx=sinxcosx+
f(x)=2sin^2-2√3*sinX*cosX+1π=1-cos2X-√3*sin2X+1=2-2sin(2X+π/3)T=2π/2=π
y=f(x)=(sinx)平方-根号3sin(pai+x)*cosx=(1/2)(1-cos2x)+根号3sinxcosx=(√3/2)sin2x-(1/2)cos2x+1/2=sin(2x-π/6)
f(x)=cos^2x+√3sinx*cosx=(cos2x+1)/2+√3/2sin2x=√3/2sin2x+1/2cos2x+1/2=sin(2x+π/6)+1/2所以当2x+π/6=2kπ+π/
因为sin(π/6)=1/2;cos(π/6)=(√3)/2所以原式等于cos(π/6)sinx+sin(π/6)cosx利用两角和公式sin(A+B)=sinAcosB+cosAsinB得到sin(
答案:cosx=-1或cosx=1/4根据和差化积公式,[sin(x+120°)-sin(x-120°)]/sin(x+120°)*sin(x-120°)=4根号3/3,(2cosxsin120°)/
f(x)=a*b=sin^x+根号3*cosxsinx=sin平方x+2分之根号3*sin2x
=2sinx*cosx-2根号3cosx的平方先2倍角公式然后合一变形=sin(2x-pai/3)
f(x)=2根号3*sinx/3*cosx/3-2sin平方x/3=4sinx/3﹙√3cosx/3﹣sinx/3﹚/2=4sinx/3sin﹙π﹣x﹚/3=﹣2[cosπ/3-cos﹙2x-π﹚/3
1、f(x)=sin²x+√3sinxcosx=(1-cos2x)/2+√3sin2x/2=(√3/2)sin2x-(1/2)cos2x+1=sin(2x-π/6)+1/2∴当x∈{x|(2
这个简单:f(x)=2cosx(sinxcos(pi/3)+cosxsin(pi/3))-根号33sin^2x+sinx*cosx=2sinxcosx+根号3cos2x=2sin(x+pi/3)所以:
y=根号3sinx+cosx+2012=2(根号3/2sinx+1/2cosx)+2012=2sin(x+π/6)+2012所以周期为2π最大值2014最小值2010
f(x)=sin(2x+π/3)(积化和差公式)所以最小正周期T=2π/2=π
y=2cosX*[sinXcospai/3+cosXsinpai/3]-根号3sin平方X+sinX·cosX=2cosX(1/2sinX+√3/2cosX)-根号3sin平方X+sinX·cosX=
根号12=根号(3*4)=2根号32根号3除以根号3=2
根号3cosx+sinx=-6/52(sinx/2+根号3cosx/2)=-6/5sinx/2+根号3cosx/2=-3/5sinx*cosπ/3+cosx*sin(π/3)=-3/5sin(x-π/