12x^2 xy-6y^2因式分解的过程

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因式分解题:8(x的平方-2乘y的平方)-x(7x+y)+xy怎么做?

8(x²-2y²)-x(7x+y)+xy=8x²-16y²-7x²-xy+xy=x²-16y²=(x+4y)(x-4y)

因式分解题 x^2-xy-2y^2-x-y

x^2-xy-2y^2-x-y=(x^2-xy-2y^2)-(x+y)=(x-2y)(x+y)-(x+y)=(x+y)(x-2y-1)

再问一题分解因式2x^2+xy-y^2-4x+5y-6

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+(2x+2y)-6x+3y-6=(2x-y)(x+y)+2(x+y)-6x+3y-6=(x+y)

分解因式的3道题目1 分解因式2x²+7xy+2y²-5y-22 分解因式6x²-13xy

2.6x²-13xy+6y²+22x-23y+20=(2x-3y)(3x-2y)+22x-23y+4×5=(2x-3y+4)(3x-2y+5)3.(x²+4x+8)

分解因式:x^2+3xy+2y^2+5x+8y+6

x^2+3xy+2y^2+5x+8y+6=(x+y)(x+2y)+5x+8y+6=(x+y+3)(x+2y+2)x+y3x+2y2

分解因式2x²y-x³-xy²

解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²

分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)

原式=(xy)2+2xy+3-2(x+y)-1-(x+y)2+2(x+y)-1,=(xy)2+2xy+1-(x+y)2,=(xy+1)2-(x+y)2,=(xy+1+x+y)(xy+1-x-y),=(

分解因式4x^2-12xy+9y^2-2x+3y-6

4x^2-12xy+9y^2-2x+3y-6=(4x^2-12xy+9y^2)-(2x-3y)-6=(2x-3y)^2-(2x-3y)-6=(2x-3y+2)(2x-3y-3)

用因式分解法解方程:2X²+XY-6Y²=0

2X²+XY-6Y²=0(2x-3y)(x+2y)=02x-3y=0或x+2y=0x=3/2y或x=-2y

分解因式x^2-6xy+9y^2-2x+6y=

x^2-6xy+9y^2-2x+6y=(x^2-6xy+9y^2)-(2x-6y)=(x-3y)^3-2(x-3y)=(x-3y)(x-3y-2)

分解因式 3x^3+2x^2y-19xy^2+6y^3

3x^3+2x^2y-19xy^2+6y^3=(3x^3-x^2y)+(3x^2y-19xy^2+6y^3)=x^2(3x-y)+y(3x-y)(x-6y)=(3x-y)(x^2+xy-6y^2)=(

12x^2+xy-6y^2 怎么分解因式

12x^2+xy-6y^2=(4x+3y)(3x-2y)

如何用交叉相乘法分解因式:12X^2+XY-6Y^2

3x-2y4x3y再问:什么意思??能详细一点吗??再答:3×4=12x^2前的系数-2×3=6y^2前的系数交叉相乘,得到的系数相加就是xy前的系数

分解因式:6x^3-5x^2y-3xy^2+2y^3

6x^3-5x^2y-3xy^2+2y^3=6x^2*(x-y)+x^2y-xy^2-2y^2(x-y)=6x^2*(x-y)+xy(x-y)-2y^2(x-y)=(x-y)(6x^2+xy-2y^2

分解因式:x^2+xy-6y^2-6x+2y+8

x^2+xy-6y^2-6x+2y+8=(x-2y)(x+3y)-(2x+6y)-(4x-8y-8)=(x-2y)(x+3y)-2(x+3y)-4(x-2y-2)=(x+3y)(x-2y-2)-4(x

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解

分解因式2x^2+3xy-2y^2-x+8y-6

原式=2x^2+(3y-1)x-2(y^2-4y+3)=2x^2+(3y-1)x-(2y-2)(y-3)=(x+2y-2)(2x-y+3).

x^3+3x-4,4x^2+2x-y-y^2,x^3-y^3-x^2y+xy^2.求分组分解法分解因式

x^3+3x-4=x^3+(x^2-x^2)+(4x-x)-4=x^3+x^2+4x-x^2-x-4=(x^2+x+4)x-(x^2+x+4)=(x^2+x+4)(x-1)4x^2+2x-y-y^2=

分解因式 -2x²y-12xy²+8xy³=?

授人以鱼不如教人以渔,解这样的题关键还是要有思路,不能向上面的人只给答案,将来你还是会遇到问题.思路如下:-2x²y-12xy²+8xy³=xy(8y^2-2x-12y)

分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)

原式=(x+y)(x+y)+2(x+y)xy+(xy)^2-1^2=(x+y)^2+2(x+y)xy+(xy)^2-1=(x+y+xy)^2-1=(x+y+xy-1)(x+y+xy+1)=(x+y+x