证明log9 4=log 3 2

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log32乘以[根号(2+根号三)-根号(2-根号三)] 32是底数

[3^(1/2)+1]^2=4+2(3)^(1/2),2+3^(1/2)=[3^(1/2)+1]^2/2,[2+3^(1/2)]^(1/2)=[3^(1/2)+1]/2^(1/2).[3^(1/2)-

已知logm27*log94=6,求m的值.(m,9是底数)

原式=lg27/lgmXlg4/lg9=3lg3/lgmX2lg2/2lg3,则m=根号2

(log43+log83)(log32+log92)=

解题思路:考查对数式的化简解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/read

证明、、

解题思路:位置关系解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph

若log32=m,log35=n,则lg5用m,n表示为______.

∵log32=m,log35=n,∴lg2lg3=m,lg5lg3=1−lg2lg3=n,1-lg2=nlg3,∴lg2=mlg3,∴1-mlg3=nlg3,∴lg3=1m+n,lg5=nlg3=n×

利用对数换底公式化简:(log43+log83)(log32+log92)

:(log43+log83)(log32+log92)=(lg3lg4+lg3lg8)•(lg2lg3+lg2lg9)=(lg32lg2+lg33lg2)•(lg2lg3+lg22lg3)=3lg3+

设a=30.5,b=log32,c=cos23

a=30.5>30=1,0=log31<b=log32<log33=1,c=cos23π=-cosπ3<0,∴c<b<a.故答案为:c<b<a.

(log23+log89)(log34+log98+log32)=______.

(log23+log89)(log34+log98+log32)=(log827+log89)(log916+log98+log94)=log8243•log9512=lg35lg8×lg83lg32

(log32+log92)•(log43+log83)= ___ .

(log32+log92)•(log43+log83)=(log32+12log32)•(12log23+13log23)=log3232•log2356=32×56=54故答案为:54

(log43+log83)(log32+log92)

(log43+log83)(log32+log92)=(log23/log24+log23/log28)(log32+log32/log39)=(log23/2+log23/3)(log32+log3

证明1=0.9999999999

1/3等于0.3333333331/3乘以3等于1也等于0.999999999

若log32 9=p,log3 5=q,如何用p.q表示lg5?

P=lg9/lg32=2lg3/5lg2=2lg3/5(lg10-lg5)=2lg3/5(1-lg5)...(1)q=lg5/lg3lg5=qlg3...(2)由(1)得lg3=5p(1-lg5)/2

设a=log32,b=log52,c=log23,则a,b,c的大小关系为______.

∵1=log33>a=log32>log31=0,b=log52<log32=a,c=log23>log22=1,∴c>a>b.故答案为:c>a>b.

log32×log89过程 3和8是底数,2和9是真数

因为log89=log2^33^2=2/3log23,log32*log23=1那么,log32×log89=2/3