计算(2x (x方-1))-1 x-1的结果是
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x-x分之1=3x^2-2+1/x^2=9x^2+1/x^2=11x^4+1=11x^2x^4=11x^2-1x-x分之1=3x^2-1=3xx^2=3x+1x的四次方-2x的三次方-2x的二次方-7
令x=tana,上方程可化简为:arccos│cos2a│+arcsin│sin2a│+arccot│cot2a│=π,当a∈(-π/2,π/2)时,tana∈(-∞,+∞),tana与任意实数一一对
依次为:(x-3)(x+1);(x+9)(x-2);(x-4)(x+1);(x+6)(x-1);(x-4)(x-9);(2x+1)(x+1)
:(x+5)^2(x-5)^2-(2x+1)^2(2x-1)^2这个式子利用“乘积的乘方法则”和“平方差公式”,然后再两个二项式相乘即可.=[(x+5)(x-5)]^2-[(2x+1)(2x-1)]^
4x的三次方除以(-2x)²-(2x²-x)/(1/2x)=x-4x+2;=2-3x;手机提问的朋友在客户端右上角评价点【满意】即可.
(2x-1)^2*(2x-1)^3+(2x-1)^4*[-(2x-1)]=(2x-1)^5-(2x-1)^4*(2x-1)=(2x-1)^5-(2x-1)^5=0
由(x^4-x²-4x-4)/(x-2)(x+1)=[x²(x²-1)-4(x+1)]/(x-2)(x+1)=[x²(x-1)(x+1)-4(x+1)]/(x-
原式=[x/(x-1)-x/(x+1)(x-1)]÷[x(x-1)/(x-1)²]=[x/(x-1)-x/(x+1)(x-1)]÷[x/(x-1)]=[x/(x-1)-x/(x+1)(x-1
1/x-1再问:要过程。。再答:
(3x^4-3x²+1)(x^4+x²-2)=(3x^4-6x²+1)(x²+2)(x²-1)=(3x^4-6x²+1)(x²+2
x²-4x+3-(x²-4x+4)=x²-x²-4x+4x+3-4=-1
原式=(x+5+x-5)(x+5-x+5)-(2x+1-2x+1)(2x+1+2x-1)=12x
1):(-x-y)(x+y)二次方=-(x+y)(x+y)²=-(x+y)³;2)(y-x)(x-y)的三次方=-(x-y)(x-y)的3次方=-(x-y)的4次方;很高兴为您解答
利用平方差公式Tn=(1+x)(1+x的平方)(1+x的四次方).(1+x的2n次方)=(1-x)(1+x)(1+x的平方)(1+x的四次方).(1+x的2n次方)/(1-x)=(1-x的平方)(1+
(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x
(x²-1)/(x²+x)÷[x-(2x-1)/x]=(x+1)(x-1)/[x(x+1)]÷(x²-2x+1)/x=(x-1)/x*x/(x-1)²=1/(x
(1/x的二次方+x)+(2/x的二次方+4x+3)+(3/x的二次方+9x+18)=1/[x(x+1)]+2/[(x+1)(x+3)]+3/[(x+3)(x+6)]=[(1/x)-1/(x+1)]+
1.原式=x-1分之x^2-(x+1)=(x-1分之x^2)-(x-1分之x^-1)=(x-1)分之1第二题可不可以写得再清楚一点,看起来好像有点乱诶~
【1】(x四次方)²÷(x四次方)²*(x²)²*x²=x的8次方÷x的8次方*x的4次方*x的2次方=x的6次方【2】(x+y)五次方÷(﹣x-y)