解分式方程6 x² x=x² x 1
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/17 23:31:08
方程两边乘以(x-1),得5-(3-x)=2(x-1),整理得5-3+x=2x-2,解得x=4.检验得x=4是原方程的解.故选A.
将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(
Х=1再问:过程?再答:(6x-1)×(2x-5)=(4x-7)×(3x+2)然后拆开,简化最后就得答案了再问:能不能帮忙检验一下,我刚才检验一下,好像不等于1再答:把1带进去,就可以了再问:可代进去
是X/(X-2)-(1-X^2)/(X^2-5X+6)=2X/(X-3)吗?首先因式分解(X^2-5X+6)=(X-2)(X-3),显然X不等于2且X不等于3,所以等式两边同乘以(X-2)(X-3)得
6x/(x+1)+2/(x^2+2x+1)=33x/(x+1)+1/(x+1)^2=33x(x+1)+1=3(x+1)^23x^2+3x+1=3x^2+6x+36x-3x=1-33x=-2x=-2/3
先看一个式子.1/n-1/(n+1)=1/n(n+1).这个等式容易理解,通分就行了.在原式中,x-2比x-1小1,x-7比x-6小1.所以可以把原等式进行移项,目的是通分后使分子为1,从而达到使分子
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
7/(x^2+x)+3/(x^2-x)=6/(x^2-1)7/x(x+1)+3/x(x-1)=6/(x-1)(x+1)分子分母同乘以x(x-1)(x+1),得7(x-1)+3(x+1)=6x10x-4
这道题不用那么复杂.先移项.(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/( x-9)再通分.(x-4)(x-6)/(x-5)(x-6)-(x-5)(x
(3x-6)/(x^2+x-6)=(4x+4)/(x^2-3x-4)3(x-2)/[(x+3)(x-2)]=4(x+1)/[(x-4)(x+1)]3/(x+3)=4/(x-4)4(x+3)=3(x-4
如果你没有计算出错的话,x1=2,是方程的増根,因为x=2时,分母2-x=0..
x/(x-2)-(x-1)/(x²-5x+6)=2/(x-3)∵x²-5x+6=(x-2)*(x-3)≠0∴x≠2,且x≠3两边同时乘以(x-2)*(x-3)得X(x-3)-(x-
左右两边同乘以(X-5)(X-6)(X-8)(X-9)得到(X-4)(X-6)(X-8)(X-9)-(X-5)(X-5)(X-8)(X-9)=(X-5)(X-6)(X-7)(X-9)-(X-5)(X-
x/(x-5)=(x-2)/(x-6)两边同乘惟(x-5)(x-6)x(x-6)=(x-2)(x-5)x^2-6x=x^2-7x+10x=10检验,代回到方程左边=10/(10-5)=2右边(10-2
(5x-4)/(x-2)=(4x+10)/3(x-2)-1两边乘3(x-2)3(5x-4)=4x+10-3(x-2)15x-12=4x+10-3x+615x-12=x+1614x=28x=2经检验,x
(1/x+4)+(1/x+6)=(1/x+3)+(1/x+7)1/(x+4)-1/(x+3)=1/(x+7)-1/(x+6)(x+3-x-4)/(x+4)(x+3)=(x+6-x-7)/(x+7)(x
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你
设t=x²+x6/t=t+16=t²+tt²+t-6=0(t+3)(t-2)=0t=-3或t=2x²+x=-3x²+x+3=0x²+x+1/
1/x+6+1/x+4=1/x+7+1/x+31/x+6-1/x+7=1/x+3-1/x+41/(x+6)(x+7)=1/(x+3)(x+4)(x+3)(x+4)=(x+6)(x+7)x^2+7x+1
1/x+5+1/x+8=1/x+6+1/x+71/x+5-1/x+6=1/x+7-1/x+8(x+6)/[(x+5)(x+6)]-(x+5)/[(x+5)(x+6)]=(x+8)/[(x+7)(x+8