作业帮编程找出四位整数abcd中满足下述关系的数有多少种
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/27 14:45:37
正代码：For i = 1 To 10000If (i Mod 3 = 2 And&nbs
PrivateSubCommand1_Click()Dimx,y,z,a,bAsIntegerFora=10To31'9的平方是2位数,所以从10开始,32的平方是4位数,所以到31为止b=a*ax=
#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);
/*1100x+11y=11(100x+y)=n^2,0
#includemain(){inti,k;for(i=1000;i
#include#includevoidmain(){intm,a,b,c,d,sum;clrscr();for(m=1000;m
#include"math.h"main(){intm,i,k,h=0,leap=1;printf("\n");for(m=0;m
#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i
PrivateSubForm_Click()DimiAsIntegerDimaa,bbAsIntegerFori=1000To9999aa=iMod100bb=Int(i/100)Ifi=(aa+bb
PrivateSubCommand1_Click()DimIAsInteger,JAsIntegerDimAAsInteger,BAsIntegerDimSAsString,NAsIntegerDim
a=input('请输入一个四位数整数：');ifa>999&&a
这个是水仙花问题,可以完成的,源程序：#include#includevoidmain(){inti,j,k,a;for(a=100;a
input"请输入4位数字:"tonshuziifvartype(nshuzi)='N'cshuzi=allt(str(nshuzi))iflen(cshuzi)=4cxulie='零壹贰叁肆伍陆柒捌
if(((idiv100)+(imod100))*((idiv100)+(imod100))=i)即i:=1000to9999就是i从1000到9999就是游遍所有的4位数字idiv100（取商不取余
#includevoidmain(){inti,j=0,a,b,c;for(i=100;i
#includeintmain(void){intmax,min;inta,i;printf("Input10interger:");scanf("%d",&a);max=min=a;for(i=0;
int getOrdNum(int num){int res = 0;res += (num % 10)&
# include <stdio.h>int fun(int *a){ int i,j=0,qw,bw,sw,gw,
nd()产生一个大于等于0且小于1的随机数要产生[m,n]中随机的整数公式：int((n-m+1)*rnd)+mint(rnd()*1000)表达式产生大于0,小于1000的整数int(rnd()*9
intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(