编写程序c语言计算2和-3的0到5次幂.

#includeintmain(){inti,j,sum,result=0;for(i=1;i

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

#include "stdio.h"int main(){    float i,s,t; &nbs

intarea(intx,inty){returnx*y;}intgri(intx,inty){return2*(x+y);}

#includemain(){doublex,y;scanf("%lf",&x);if(x

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j,k,sum;for(sum=1,i=0;i

#include#includeintmain(){intsum=0;intindex=0;for(index=1;index

TCHARszBuff=newTCHAR[10000];这里把所有的内容放到szBuff里intaverage,iWordNum,iLine;while(*szBuff++!='\0'){if(*sz

#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

//m与n的值不能太大,且用空格分隔.如：53#includeintfun(intn){\x09if(n==0||n==1)return1;\x09elsereturnn*fun(n-1);}void

#includevoidmain(){doubler,s,l;printf("请输入圆的半径\n");scanf("%lf",&r);s=3.14159*r*r;l=2*3.14159*r;print

#include <stdio.h>int main(){  float x, tax = 0; 

#includeintmain(){intlength,width,perimeter;printf("长：");scanf("%d",&length);printf("宽：");scanf("%d"

#includeintmain(intargc,char*argv[]){intm,n;inti;intsum;printf("Pleaseinputmandn:\n");scanf("%d%d",&

因为3个加法的运算规律是相同的,使用一个函数来计算循环值#includeintfun(intn)//计算累加结果函数{//这里还可以判断下n是否小于等于0intsum=0;inti;for(i=1;i

main(){inta,b,c;c=a+b;scanf("%d%d",&a,&b);printf("%d",c);}

#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i

#includeintmain(){inti,s=0;for(i=1;i

m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.