用配方法解决关于x的方程2X方加mx加2n等于0
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1.2x^2-x+1=2(x^2-2*1/4*x+1/16)+7/8=2(x-1/4)^2+7/8>=7/8>02.x^2-6x-4n^2-32=0x^2-6x+9-4n^2=41(x-3)^2-(2
解析:原方程可化为:x²-2ax+a²=b²(x-a)²=b²解得:x-a=b或x-a=-b即x=a+b或x=a-
x²+6x-3=0(x+3)²-12=0x+3=±2√3x=-3+2√3或x=-3-2√3
原式=x²-2ax+a²-a²-8a²=(x-a)²-9a²=(x-a+3a)(x-a-3a)=(x+2a)(x-4a)
题目是不是写错了2x^2-5x^2=3-3x^2=3x^2=-1无解再问:再问:饿再问:是错了……再问:我算一半不会算了…再答:
5x²-6x-8=0(5x-4)(x+2)=0x=5分之4或者-2
3X²-6X+1=03X²-6X=-1X²-2X=-1/3X²-2X+1=-1/3+1=2/3(x-1)²=2/3x-1=±√6/3x=1±√6/3
X^2+6X-1=0x^2+6x+9-10=0(x+3)^2-(√10)^2=0(x+3+√10)(x+3-√10)=0x1=-3-√10x2=-3+√10
(x+1)×(x+6)再答:错了,是减号再答:(x-1)(x-6)再问:不对吧再答:再答:第一次错了,换成减号就对了,答案是x等于1或者6再答:(^_^)(^_^)
解由2x²+4x+1=0得2x²+4x+2-1=0即2(x²+2x+1)-1=0即2(x+1)²-1=0即2(x+1)²=1
3x方-2x-1=03(x²-2x/3+1/9)-1/3-1=03(x-1/3)²=4/3(x-1/3)²=4/9x-1/3=±2/3x1=1/3+2/3=1x2=1/3
∵x2-2x-m=0,∴x2-2x=m,∴x2-2x+1=m+1,∴(x-1)2=m+1.故选D.
0.4x平方-0.8x=1两边同时乘以5得2x平方-4x=52x平方-4x+2=72(x平方-2x+1)=72(x-1)平方=7(x-1)平方=2分之7x-1=±2分之根号14x=1±2分之根号14x
(x-p)^2=7x^2-2px+p^2=7x^2-2px+p^2-7=02p=6p=3p^2-7=-qq=7-p^2x^2-6x-q=2x^2-6x-(7-p^2)=2x^2-6x-7+p^2=2x
再答:你上初三?
1/4*x^2-x+1=0x^2-4x+4=0(x-2)(x-2)=0x1=x2=2(2x+1)^2=(1-3x)^24x^2+4x+1=9x^2-6x+15x^2-10x=0x^2-2x=0x(x-
ax平方+bx+c=0配方为a﹙x+b/2a﹚²=﹙b²-4ac﹚/4a²,当b²-4ac≥0时,方程有实根,x=[-b±√﹙b²-4ac﹚]/2a.
x²-3/2x=1x²-3/2x+9/16=1+9/16所以变形为(x-3/4)²=25/16x-3/4=±5/4x=-1/2,x=2再问:这是个选择提,但你给的答案没在