根号下x的四次方加x的平方乘y的平方-搜答案-智慧作业帮

√(x^5+x^4y²)=x²√(x+y²)√(a^5+2a³b²+ab^4)=√{a(a²+b²)²}=(a²

4X^2+Y^2-4X-6Y+10=0(4X^2-4X+1)+(Y^2-6Y+9)=0(2X-1)^2+(Y-3)^2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等

x^2-4x+y^2-10y+29=0x^2-4x+4+y^2-10y+25=0(x-2)^2+(y-5)^2=0x=2,y=5x^2y^2+2x^3*y^2+x^4y^2=x^2y^2(1+2x+x

(x+y)²=162xy=6,xy=3x²y²=92x²y²=18x的四次方加y的四次方=（x²+y²）²-2x&sup

x的四次方+y的四次方-3乘x的平方乘y的平方==x^4-2x^2y^2+y^4-x^2y^2=(x^2-y^2)^2-x^2y^2=(x^2+xy-y^2)(x^2-xy-y^2)

括号应该成对,还有一个括号在哪里?能不能把你的叙述用数学的语言表达出来?

/>x的四次方加2x的三次方加x的平方加1加2乘（x加x的平方）=x^4+2x^3+x^2+1+2(x+x^2)=x^4+2x^3+x^2+1+2x+2x^2=x^4+2x^3+3x^2+2x+1=x

√(9x^2+36x^4)=√[9x^2(1+4x^2)]=3*|x|√(1+4x^2)

∵x^2+y^2-2x+4y+5=0配方：∴(x-1)^2+(y+2)^2=0那么x-1=0且y+2=0所以x=1,y=-2∴(x^4-y^4)/(2x^2+xy-y^2)*（2x-y)/(xy-y^

x=(-a^2-√a^4-4a)/2a=(-a^2-a^2-4a)/2a=(-2a^2-4a)/2a=-a-2a*x^2+a^2x-1=a(-a-2)^2+a^2(-a-2)-1=a(a^2+4a+4

原式=x^4+4x²y²+4y^4-x²y²=(x²+2y²)²-(xy)²=(x²+xy+2y²)

先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+

x的四次方-3x的平方y的平方+2y的四次方=(x²)²-3x²y²+2(y²)²=(x²-y²)(x²-2y

x^4+y^4=x^4+2x^2y^2+y^4-2x^2y^2=(x^2+y^2)^2-2x^2y^2=(x^2+y^2+√2*xy)(x^2+y^2-√2*xy)

6X的四次方减11

原式=[x/(x-y)]*[y^2/(x+y)]-[x^4y/(x^2+y^2)(x^2-y^2)]/[x^2/(x^2+y^2)]=xy^2/(x^2-y^2)-x^2y/(x^2-y^2)=xy(

你确定是这样的式子?424x+3x+36y如果是这样的话应该是分不出来的

X四次方+X²Y²+X²Y²-X²Y²+Y四次方=（X²+Y²）²-X²Y²

x²+2xy+y²+x⁴-y⁴=(x+y)²+(x²+y²)(x²-y²)=(x+y)²+(x&