方程x立方-6x² 9x-10=0

判断方程的元数只要看方程中有几个未知数就可以了,显然此方程是一元,又因为未知数x还有做除数的而且有多个等式,所以此方程是一元二次方程组.楼主应该可以自行解决吧

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

[1-1/(x-4)]+[1-1/(x-8)]=[1-1/(x-7)]+[1-1/(x-5)]1/(x-4)+1/(x-8)=1/(x-7)+1/(x-5)(x-4+x-8)/(x-4)(x-8)=(

若x为非整数,则等式左边应该是一个整数,而等式右边肯定是一个小数,则方程无解若x为整数,则可以化简为x^3+x^2+x=-1移项x^2(x+1)+(x+1)=0(x^2+1)(x+1)=0x^2+1>

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

(x+3)(x-4)(x+2)-x3=251(x2-4x+3x-12)(x+2)-x3=251x3+2x2-x2-2x-12x-24-x3=251x2-14x-275=0(x+11)(x-25)=0x

x³-3x²-x²+x+6=0x²(x-3)-(x²-x-6)=0x²(x-3)-(x+2)(x-3)=0(x-3)(x²-x-2

/>因为：x-5/x-6+x-8/x-9=x-7/x-8+x-6/x-7,所以：1+1/(x-6)+1+1/(x-9)=1+1/(x-8)+1+1/(x-7)即：1/(x-6）+1/(x-9)=1/(

(1)(X+7)/(X+6)+(X+9)/(X+8)=(X+10)/(X+9)+(X+6)/(X+5)这类方程重在运算的技巧性,观察分母7+9=10+6;6+8=5+9所以先移项:(X+7)/(X+6

(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/

4x^2(x+2)-9(x+2)=0(x+2)(4x^2-9)=0(x+2)(2x-3)(2x+3)=0x=-2,1.5,-1.5

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/

这道题不用那么复杂.先移项.(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/( x-9)再通分.（x-4)(x-6)/(x-5)(x-6)-(x-5)(x

这种题目要回凑数我以前都是看答案反着推在大型考试中不会出现没有一定的数感不是那么容易做的做出来没有意义建议看答案反着推吧

x(x²-9)-(x²-9)=0(x²-9)(x-1)=0(x+3)(x-3)(x-1)=0x=-3,x=3,x=1

原式可化为：x^4+2x^3-6x^2+2x-1=0x^2(x^2+2x-3)-(3x^2-2x-1)=0x^2(x+3)(x-1)-(3x+1)(x-1)=0(x-1)(x^3+3x^2-3x-1)

原式可化简为：(-x方+8+6x立方)+(-2x立方+5x-7)=-x方+8+6x立方-2x立方+5x-7.（去括号）=4x立方-x方+5x+1.（合并同类项）=4x（-2）立方-（-2）平方+5x（

把x=-1代入方程-10k+1-9=0k=-4/5代入方程得-8x-x-9=0

解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2