10*5800 (y-10)*5800*70%=5800*y*80%

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/15 10:10:42
已知x,y互为相反数,求式子3x-10+3y+5x/y(y不等于0)

3x-10+3y+5x/y=3x+3y-10+5x(-1)=0-10-5=-15

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3

x-y/7-x+y/10=1/2两边乘7010x-10y-7x-7y=353x-17y=35(1)2(x-y)+5(x+y)=32x-2y+5x+5y=37x+3y=3(2)(2)*3-(1)*79y

(3y-1)/4-1=(5y-7)/6 9y-3-3=10y-14 9y-10y=-14+3+3 -y=-8 y=8

是否代人检验了?第二步建议应先化为有括号的:3(3y-1)-12=2(5y-7)解得y=-1解题时,建议应按步骤有序的完成,养成良好的习惯.再问:我是知道错了,但我主要要的是过程,看我是错在哪?再答:

(7x-10y)-(-10y-5x)=?

(7x-10y)-(-10y-5x)=7x-10y+10y+5x=12x再问:7x-10y+10y+5x似乎等于2x+10y再答:-10y+10y=0

已知x+y=10,求[(x+y)^2-(x-y)^2-2y(x-y)]÷5y的值

[(x+y)²-(x-y)²-2y(x-y)]÷5y=[X²+2XY+Y²-X²+2XY-Y²-2XY+2Y²]÷5Y=[2Y(X

y满足x-y+2≥0,x+y-4≥0,2x-y-5≤0 求X^2+Y^2-10Y+25的最小值

在直角坐标系里面画出x-y+2≥0,x+y-4≥0,2x-y-5≤0这三条直线,围着的那一块就是x,y的取值范围,X^2+Y^2-10Y+25等于x,y的取值范围里点到(0,5)点的距离的平方.在x,

5(2x-7y)-(4x-10y)全过程

10x-35y-4x+10y再答:6x-25y

5(x-y)'3+10(y-x)'2;

1.=5(x-y)'3+10(x-y)'2=5(x-y)'2(x-y-2)2.=(4a'2)'2-2*(4a'2)*(9b'2)+(9b'2)'2=(4a'2-9b'2)'2=(4a-3b)'2(4a

解方程:10y-2(7y-2)=5(4y+3)-2y怎么解

先将括号里的全部展开10y-14y+4=20y+15-2y然后在合并同类项,将等式左边的带y的全部移到右边去4=20y-2y-10y+14y+154=22y+1522y=-11y=-1/2

化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)

(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)=x-2x-3x-4x-..-10x+y*(1-1/2-1/6-1/12-..1/90

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66

2/(x+y)+5/(x-y)=189/(x+y)-10/(y-x)=66设x+y=a,x-y=b,原方程化为2/a+5/b=18-----1(1)9/a+10/b=66-------(2)(2)-(

解一元一次方程 3- 5-2y/5=4- 10-4y/10+ y+2/2

4y/10-2y/5-y=4-10+1-3+5所以4y/10-4y/10-y=-3-y=-3,y=3

10a(x-y)²-5a(y-x) 因式分解

=5a(y-x)(2y-2x-1)

10y+2(7y-2)=5(4y+3)+3y怎么算

10y+2(7y-2)=5(4y+3)+3y10y+14y-4=20y+15+3y10y+14y-20y-3y=15+4y=19

因式分解x²-5x+10y-4y²

x²-5x+10y-4y²=(X+5/2)²-(2y+5/2)²=(x+5/2+2y+5/2)(x+5/2-2y-5/2)=(x+2y+5)(x-2y)

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-

[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-x)^29^-x*27^y=3^-2x*3^3y=3^(-2x+3y)=3^(-