5(x-y)'3+10(y-x)'2;
数学(x-y)^5*(y-x)^3*(x-y)^2
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
(2X-3y)-(5x-y)
化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)
5(x-y)'3+10(y-x)'2;
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
10/x+y+3/x-y=-5 15/x+y-2/x-y=-1(用换元法解此方程组)
2(2x+3y)(3x+2y)-(6x-y)(2x-5y)