已知y=1,y=x,y=x^2是某二阶非齐次线性微分方程的三个解

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已知集合A={(x,y)|x≥1y≤1x-y≤2}

由题意集合A={(x,y)|x≥1y≤1x-y≤2}表示的可行域如图三角形,集合B={(x,y)|xcosα+ysinα-1=0,α∈[0,2π)},表示的区域是单位圆的切线,若A∩B≠∅,即图中红色

已知2/x+2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

2/x+2/y=根号24(2y+2x)/xy=2√6x+y=xy√6x/y(x-y)-y/x(x-y)=1/(x-y)[(x/y-y/x)]=1/(x-y)[(x²-y²)/xy]

已知2/x 2/y=根号24,求 x/y(x-y) - y/x(x-y)的值

你的题目有点问题我这样做了x/{y(x-y)}-y/{x(x-y)}=(x平方-y平方)/{xy(x-y)}=(x+y)/xy2/x+2/y=2(x+y)/xy=根号24

已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²

原式=(2x-y)(x+y)/(2x-y)^2=(x+y)/(2x-y)x/y=2x=2y原式=3y/3y=1

已知正实数x,y满足x+2y=4,则1x+1y

由已知1x+1y=(1x+1y)(x+2y)×14=(3+2yx+xy)×14≥(3+2 2yx×xy)×14=3+224.等号当且仅当2yx=xy时等号成立.∴1x+1y的最小值为3+22

已知:3x=8y.求(1)x+y/y (2)2x+3y/x-2y

3x=8yx/y=8/3(1)x+y/y=x/y+1=8/3+1=11/3(2)2x+3y/x-2y分子分母同时除以y得=(2x/y+3)/(x/y-2)=(16/3+3)/(8/3-2)=(25/3

数学题已知p=x^/x-y-y^/x-y,q=(x+y)^-2Y(X+Y),

你的题是什么意思?“^/”是什么意思?

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?

X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5

已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

1.已知1/x+1/y=-1/x+y,则y/x+x/y=?

1.1/x+1/y=(x+y)/xy=-1/(x+y)去分母可得,(x+y)^2+xy=0即x^2+y^2=-3xy所以y/x+x/y=(x^2+y^2)/xy=-32.由1/x-1/y=5可得y-x

已知4x=9y求(1)x+y/y (2)y-x/2x

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

已知(2x+1)*2+y*2+2y+1=0 求{(x*2+y*2)-(x-y)*2+2y(x-y)}/(2y)

(2x+1)^2+y^2+2y+1=0(2x+1)^2+(y+1)^2=0(2x+1)^2=0,(y+1)^2=0x=-1/2,y=-1{(x^2+y^2)-(x-y)^2+2y(x-y)}/(2y)

已知x,y满足约束条件:x-y+1>=0,x+y-2>=0,x

最小值0.5,1.5,-1最大值1,1,-1/3约束区域是一个三角形,把三角形的三个顶点代入.可以检验出最大值最小值.

已知x=2+根号3,y=2-根号3,计算代数式(x+y/x-y-x-y/x+y)乘以(1/x^2-1/y^2)

即xy=2²-(√3)=4-3=1原式=[(x+y)²-(x-y)²]/(x+y)(x-y)*[-(x²-y²)/x²y²]=(x

1、已知x=2y,则x-5y/x+y=()

1)x-5y/x+y=2y-5y/2y+y=-12)x=3z/5,y=4z/52x²-3xy+2xz/2y²-4x²+z²=(18z²/25-36z&

已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y

1,-3再问:过程。。。再答:★(x²-2x)+(y²-4y)=5★(x-1)²+(y-2)²=1+4-5★(x-l)²=0,(y-2)²=

已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(

原式=x-x+x-x+……-x+(2-1+4-3+5-4+……+2008-2007-2009)y=0+(1×1004-2009)y=-1005y=1005/2