8.64 7.2x=44.64 解方程
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(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1
((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30
2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0
(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x
我给个思路吧(X+2-1/X+2)-(X+3-1/X+3)=(X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决
只有一个实根.设f(x)=x^3+2x-19为单调增函数.所以只有一个实根.下面来求这个实根由于f(2)=-7f(3)=11所以这个根在(2,3)内.利用二分法求这个解.取x0=5/2f(5/2)=1
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
通分得[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
(x^2+x)(x^2+x-3)-3(x^2+x)+8=0(x^2+x)^2-6(x^2+x)+8=0(x^2+x-4)(x^2+x-2)=0x^2+x-4=0x^2+x-2=0(x+1/2)^2=1
(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(
通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你
问题是不是X2=(X+30)*(X-18)啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得:X2-X2-12X=-540,即-12X=-540,X=45*
x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/
解方程:(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开:X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得:12x=18则x=18/12=3/2