3xy 4x²y-3xy²-5x²y

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 08:10:16
已知xy/x+y=3,求代数式2x-5xy+2y/x-3xy+y

xy/x+y=3则xy=3(x+y)2x-5xy+2y/x-3xy+y=2(x+y)-5xy/(x+y)-3xy=2(x+y)-15(x+y)/(x+y)-9(x+y)=-13(x+y)/-8(x+y

已知x-y=2xy,求代数式3x-5xy-3y/x+xy-y的值

x-y=2xy3x-5xy-3y/x+xy-y=[3(x-y)-5xy]/[(x-y)+xy]=(6xy-5xy)/(2xy+xy)=1/31/x+1/y=4y+x=4xyx-5xy+y/2x+xy+

已知,xy/x+y=3,求代数式3x-5xy+3y/-x+3xy-y的值

xy/x+y=3xy=3(x+y)3x-5xy+3y/-x+3xy-y=(3x+3y)-5*3(x+y)/[-x-y+3*3(x+y)]=-12(x+y)/8(x+y)=-3/2望采纳,谢谢!

已知xy^2=-2,求-xy(x^2y^5-xy^3-y)的值.

-xy(x^2y^5-xy^3-y)=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+4-2=8+4-2=10

5x^2y/-1/2xy*3xy^2

5x^2y/-1/2xy*3xy^2=-7.5x²y²

已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=

xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7

已知X+Y分之XY=2,求-X+3XY-Y分之3X+5XY+3Y

因为X+Y分之XY=2,所以XY=2(X+Y)代入后面的分子式得:13(X+Y)/5(X+Y)=13/5

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,

已知xy=2(x+y),求(5x-xy+5y)/(3xy-x-y)的值

(5x-xy+5y)/(3xy-x-y)=[5(x+y)-xy]/[3xy-(x+y)]=[5(x+y)-2(x+y)]/[6(x+y)-(x+y)]=1/2

已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=

因为xy/(x+y)=1/2所以x+y=2xy原式=3(x+y)-5xy/(-x-y+3xy)=3*2xy-5xy/(-2xy+3xy)=xy/xy=1

已知xy/x+y=3,求代数式3x-5xy+3y/-x+3xy-y的值.

xy/x+y=3xy=3(x+y)3x-5xy+3y/-x+3xy-y=3x-15(x+y)+3y/-x+9(x+y)-y=-12(x+y)/8(x+y)=-3/2

X+y=3 xy=-5 Xy=?

X+y=3xy=-5X-y=?(x-y)^2=(X+y)^2-4xy=9+20=29则x-y=±根号29

已知x^-xy=5,xy-y^=-3,求式子3(x^-xy)-xy+y^的值

3(x^2-xy)-xy+y^2=3(x^2-xy)-(xy-y^2)=3*5-(-3)=15+3=18

已知xy/x+y=2,求代数式3x-5xy+3y/-x+2xy-y的值

xy/(x+y)=2xy=2(x+y)(3x-5xy+3y)/(-x+2xy-y)=[3(x+y)-5xy]/[2xy-(x+y)]=[3(x+y)-10(x+y)]/[4(x+y)-(x+y)]=-

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2如何化简

5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2=5xy^2-3xy^2+(4xy^2-2x^y)+x^2y-xy^2=5xy^2-3xy^2+4xy^2-2x^y+x^2y-

若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值

x+y=5xy(2x-3xy+2y)/(x+2xy+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问:若x+1/x=3,求(x

已知x-y=3xy,且xy不等于0,则-3x+6xy+3y/(7x-5y)-9xy-(3x-y)

因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-

已知xy^2=-2 求-xy(x^2y^5-xy^3-y)

原式=-xy²(x²y^4-xy²-1)∵xy²=-2原式=2((-2)²-(-2)-1)=10

2x平方y-2xy+3xy平方+5+2xy+x平方y-3xy平方-3 过程!

2x平方y-2xy+3xy平方+5+2xy+x平方y-3xy平方-3=2x²y-2xy+3xy²+5+2xy+x²y-3xy²-3=3x²y+2