(y-6)(x-12)

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2(2x+3y)(3x+2y)-(6x-y)(2x-5y) =12x^2+26xy+12y^2-

平方的意思再问:你确定吗再答:那个符号带数字几,就是几次方再答:确定

用换元法解方程组 2分之x+y+3分之x-y=6 2(x+y)+(x-y)=12

解析:令x+y=m,x-y=n,那么原方程组可化为:{2分之m+3分之n=6(1){2m+n=12(2)(1)×6可得:3m+2n=36(3)(2)×2可得:4m+2n=24(4)(4)-(3)可得:

为什么我约分2x^2y(x-y)^2/12xy^2(y-x)到后面得x(x-y)^2/6y(y-x).而答案是x(y-x

把(y-x)转化成-(x-y)哦、了解了-(x-y)=-x+y=y-x比喻-(5-3)=-5+3=3-5=-2上面那个(X-Y)^2=(y-x)^2因为是平方(X-Y)^2=[-(y-x)]^2=(-

6(x-y)的三次方+12(x-y)的平方-3(y-x)的平方

6(x-y)的三次方+12(x-y)的平方-3(y-x)的平方=6(x-y)³+12(x-y)²-3(x-y)²=6(x-y)³+9(x-y)²=3(

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,

x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1

计算:(x-y)^2*(y-x)^2*(x-y)^6

(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x

6x^4y^3+12x^3y^4-24x^2y^5

6x^4y^3+12x^3y^4-24x^2y^5提取6x^2y^3=6x^2y^3(x^2+2xy-4y^3)

化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)

(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)=x-2x-3x-4x-..-10x+y*(1-1/2-1/6-1/12-..1/90

(x-y)x^6+(y-x)y^6因式分解

(x-y)x^6+(y-x)y^6=(x-y)x^6-(x-y)y^6=(x-y)(x^6-y^6)=(x-y)(x³+y³)(x³-y³)=(x-y)(x+y

解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18

x(x+y+z)=6(1)y(x+y+z)=12(2)z(x+y+z)=18(3)(1)/(2)x/y=1/2y=2x(1)/(3)x/z=1/3z=3xx(x+2x+3x)=66x^2=6x=1y=

解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12

设a=x+y,b=x-y原方程组为:a/2+b/3=6,即3a+2b=36,即:12a+8b=1444a-5b=12,即:12a-15b=36相减得:23b=108,得:b=108/23,再得:a=1

已知X.Y是实数,且X²+Y²-4X+6Y+12=0 求X+Y的最值,X-Y的最值

另一个类似的.设x-y=m,则因x、y满足x²+y²-4x+6y+12=0就是(x-2)²+(y+6)²=1直线x-y=m到圆(x-2)²+(y+6)

解方程组 x+y+z=-7 x-y=12 x+y-z=6

x+y+z=-7①x-y=12②x+y-z=6③①+③2(x+y)=-1x+y=-0.5④②+④2x=11.5x=5.75∴y=-0.5-5.75=-6.25z=5.75-6.25-6=-6.5即:方

已知x²-y²=12,x+y=6,求x,y的值

好好看哦,绝对最简单!

若X平方-Y平方=12,X+Y=6,求X,Y的值

∵x²-y²=12∴(x+y)(x-y)=12∵x+y=6…………①∴x-y=2…………②①+②得2x=8x=4把x=4代入①得4+y=6y=2∴x=4,y=2很高兴为您解答,祝你

X+Y=12,X和Y( )比例;6分之X和Y分之5,X和Y( )比例

X+Y=12,X和Y(不成)比例;6分之X和Y分之5,X和Y(反)比例对我的回答有不明白的可以追问!

已知x、y是实数,且x²+y²-4x-6y+12=0.求x²+y²的最值,x-y

楼上配方不对呀x²+y²-4x-6y+12=0.配方得:(x-2)²+(y-3)²=1表示以C(2,3)为圆心,1为半径的圆设圆上点P(x,y)那么|PO|=√

化简求值:(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.(10x+1

(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y

若|x|+y=12,x+|y|=6,那么x,y各等于多少

|x|+y=12,x+|y|=6x>=0时,x+y=12x+|y|=6,|y|-y=-6,无解x