sin(x^2+y^2)=x,求dy

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/11 14:47:26

sin(x^2+y^2)=x,求dy

sin(x^2+y^2)=x
两边同时求导,得
(x^2+y^2)'cos(x^2+y^2)=dx
(2xdx+2ydy)cos(x^2+y^2)=dx
2xdx+2ydy=dx/cos(x^2+y^2)
2ydy=dx/cos(x^2+y^2)-2xdx
dy=(dx/cos(x^2+y^2)-2xdx)/2y

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