1.(1-1/2008)(1-1/2007)(1-1/2006)...(1-1/2001)(1-1/1000)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/17 05:21:20
1.(1-1/2008)(1-1/2007)(1-1/2006)...(1-1/2001)(1-1/1000)
2.用"84"消毒液配制药液,对白色衣物进行消毒,要求按1:200的比例进行稀释,现要配制此种药液4020g,则需"84"消毒液_____g
3.已知|x+2|+(y+2)^2=0,求-3(x-2y)^3-2(2x-y)^3的值
2.用"84"消毒液配制药液,对白色衣物进行消毒,要求按1:200的比例进行稀释,现要配制此种药液4020g,则需"84"消毒液_____g
3.已知|x+2|+(y+2)^2=0,求-3(x-2y)^3-2(2x-y)^3的值
1.(1-1/2008)(1-1/2007)(1-1/2006)...(1-1/2001)(1-1/1000)
=2007/2008*2006/2007*2005/2006*.*2000/2001*1999/2000
=1999/2008
2.用"84"消毒液配制药液,对白色衣物进行消毒,要求按1:200的比例进行稀释,现要配制此种药液4020g,则需"84"消毒液_____g
x/4020=1/200
=>x=20.1
3.已知|x+2|+(y+2)^2=0,求-3(x-2y)^3-2(2x-y)^3的值
绝对值和平方的值恒为肺腑,只有两数都为0时,和才为0
所以x+2=0,y+2=0
x=-2,y-2
-3(x-2y)^3-2(2x-y)^3
=-5(x-2y)^3
=-5*(-2+4)^3
=-5*8
=-40
=2007/2008*2006/2007*2005/2006*.*2000/2001*1999/2000
=1999/2008
2.用"84"消毒液配制药液,对白色衣物进行消毒,要求按1:200的比例进行稀释,现要配制此种药液4020g,则需"84"消毒液_____g
x/4020=1/200
=>x=20.1
3.已知|x+2|+(y+2)^2=0,求-3(x-2y)^3-2(2x-y)^3的值
绝对值和平方的值恒为肺腑,只有两数都为0时,和才为0
所以x+2=0,y+2=0
x=-2,y-2
-3(x-2y)^3-2(2x-y)^3
=-5(x-2y)^3
=-5*(-2+4)^3
=-5*8
=-40
1.(1-1/2008)(1-1/2007)(1-1/2006)...(1-1/2001)(1-1/1000)
|1/2009-1/2008|+|1/2008-1/2007|+|1/2007-1/2006|-|1/2006-1/20
求1/(1/2001+1/2002+1/2003+1/2004+1/2005+1/2006+1/2007+1/2008+
求1除以(1/2001+1/2002+1/2003+1/2004+1/2005+1/2006+1/2007+1/2008
|1/2008-1/2007|+|1/2007-1/2006|+|1/2006-1/2005|+|1/2005-1/20
(1-1/2008)*(1-1/2007)*(1-1/2006).*(1-1/1001)*(1-1/1000)帮忙写出运
1/2009-1/2008|+|1/2008-1/2007|+|1/2007-1/2006|+.+|1/3-1/2|+|
|2009/1-2008/1|+|2008/1-2007/1|+|2007/1-2006/1|+.+|3/1-2/1|+
(1/2008-1)*(1/2007-1)*(1/2006-1)*...*(1/3-1)*(1/2-1)
(1/2008-1)*(1/2007-1)*(2006-1).(1/1001-1)*(1/1000-1)
计算 |1\2008-1\2007| +|1\2007-1\2006|+|1\2006-1\2005|+|1\2005-
|1/2007-1/2006|+|1/2008+1/2006|+|1/2008-1/2007|