1,计算:√(13+2√7+2√5+2√35) -(3√7+4√6+√3)/(√42+√21+3√2+6)=______
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/26 06:36:33
1,计算:√(13+2√7+2√5+2√35) -(3√7+4√6+√3)/(√42+√21+3√2+6)=___________________
√(13+2√7+2√5+2√35)-(3√7+4√6+√3)/(√42+√21+3√2+6)
=√(√7+√5+1)² - (√3√21+4√3√2+√3)/[√2√21+√21+3√2+3√2√2]
=√7+√5+1 - √3(√21+4√2+1)/[(√2+1)√21+3(√2+1)√2]
=√7+√5+1 - √3(√21+3√2+√2+1)/[(√2 +1)(√21+3√2)]
=√7+√5+1 -[√3/(√2+1)][1/(√2+1) +1/(√21+3√2)]
=√7+√5+1 -[√3(√2-1)][√2-1 +(√21-3√2)/3]
=√7+√5+1 -√3(√2-1)² - (√2-1)(√7-√6)
=√7+√5+1- 3√3+2√6- √14+2√3+√7-√6
==2√7+√5-√3+√6-√14 +1
=√(√7+√5+1)² - (√3√21+4√3√2+√3)/[√2√21+√21+3√2+3√2√2]
=√7+√5+1 - √3(√21+4√2+1)/[(√2+1)√21+3(√2+1)√2]
=√7+√5+1 - √3(√21+3√2+√2+1)/[(√2 +1)(√21+3√2)]
=√7+√5+1 -[√3/(√2+1)][1/(√2+1) +1/(√21+3√2)]
=√7+√5+1 -[√3(√2-1)][√2-1 +(√21-3√2)/3]
=√7+√5+1 -√3(√2-1)² - (√2-1)(√7-√6)
=√7+√5+1- 3√3+2√6- √14+2√3+√7-√6
==2√7+√5-√3+√6-√14 +1
1,计算:√(13+2√7+2√5+2√35) -(3√7+4√6+√3)/(√42+√21+3√2+6)=______
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