懂数学的求点拨,怎样由x²+xy-2y²=0得到=(2x-y)(x-y)求解
懂数学的求点拨,怎样由x²+xy-2y²=0得到=(2x-y)(x-y)求解
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
已知x-3y=0,求(x²-2xy+y²/x-y)-2y的值
2x+y=0,求4x²+2xy(x+y)+y³
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知x-3y=0,求2x+y/x²-2xy ×(x-y)的值
若正数x,y满足x²-y²=2xy,求(x-y)/(x+y)的值
正数x,y满足x²-y²=2xy,求x-y/x+y的值
2x²-3xy=y²=0(x,y不得o)求x/y+y/x
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y
已知3x*+xy-2y*=0,求(x/y)-(y/x)-(x*+y*)/(xy)的值.*是平方
初中数学分式已知x/y=2,求(x*x-xy+3y*y)/x*x+xy+6y*y的值