main() { int x=10; int *p1=&x,*p2; p2=p1; printf("%d\n",*p2)
main() { int x=10; int *p1=&x,*p2; p2=p1; printf("%d\n",*p2)
int *p1,*p2; p1=(int *)malloc(10); p2=p1+2; printf("p1=0x%x,
int *p1=malloc(4); int *p2=malloc(4); printf("p2-p1=%d\n",p2
int m=1,n=2,*p1=&m,*p2=n; printf("%d%d%d%d“,*p1,*p2,*p1=*p1+
int a=10,b=20,*p1,*p2; p1=&a; p2=&b; p1=p2; printf("%d,%d",*
swap(int *p1,int *p2) {int temp; temp=*p1; *p1=*p2; *p2=temp
看下面:void Swap(int *p1,int *p2) { int *p; p = p1; p1 = p2; p2
int*p,*p1,*p2,*p=*p1,*p1=*p2,*p2=*p3哪里有错.另外p=p1,p1=p2,p2=p3呢
#include void swap(int b[]) { int *p,*p1,*p2; p1=&b[0] ;p2=&
设int*p2=&x,*p1=a;p2=&b;则a和b的类型分别是什么
#includevoid main(){int *p1,*p2,a[5]={1,3,5,7,9};for(p1=a;p1
#include#includevoid fun (char *w,int n){char s,*p1,*p2;p1=w