如图所示,AB=AE,AC=AD,∠BAD=∠EAC,试说明ED=BC
如图所示,AB=AE,AC=AD,∠BAD=∠EAC,试说明ED=BC
如图,在△ABE中,AB=AE,AD=AC,∠BAD=∠EAC,BC,DE交于点O.试说明:BC=ED
如图已知ab=ad,ac=ae∠bad=∠eac是说明bc=de
如图△abe中ab=ae,ad=ac,角bad=角eac,bc,ed交与点o
如图,已知AB=AE,∠C=∠D,∠BAD=∠EAC,则BC=ED,说明理由!
如图,已知AB/AD=BC/DE=AE/AC,点B、D、E在同一直线上,试说明∠BAD=∠CBE=∠EAC
如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE
如图,在△ABE中,AB=AE,AD=AC,∠BAD=∠EAC,BC、DE交于点O.∠ABC=∠AED;
如图,在△ABE中,AB=AE,AD=AC,∠BAD=∠EAC,BC、DE交于点O.
已知在三角形ABC中,DE在BC边上,AB=AC,AD=AE.求证∠BAD=∠EAC.  
如图,∠B=∠E,∠BAD=∠EAC,AC=AD,求证:AB=AE
如图所示,在三角形ABC和三角形ADE都是等腰三角形,AB=AC,AD=AE,且∠DAB=∠EAC,则DE∥BC吗,为什