cosx -(根号3)*sinx这道题的答案是-2sin(x +pai /3)还是2sin(x +pai /3)
cosx -(根号3)*sinx这道题的答案是-2sin(x +pai /3)还是2sin(x +pai /3)
sin(x-2pai)-cos(pai-x)=(1-根号3)/2,x是第二象限的角.求:(1)sinx与cosx的值(2
f(x)=(sinx)平方+2根号3sin(x+pai/4)cos(x-pai/4)-(cosx)平方-根号3
Y=2COSX·sin(X+pai/3)-根号3sin平方X+sinX·cosX
sin(pai/3-x)等于sinx?
cos(x-pai/4)=根号2/10,x属于(pai/2,3pai/4)求sinx和sin(2x+pai/3)
已知cos(x-pai/4)=根号2/10,x€(pai/2,3pai/4).(1)求sinx的值(2)求sin(2x+
化简!f(x)=sin(pai-x)cos(3/2pai+x)+sin(pai+x)sin(3/2pai-x)
已知函数y=f(x)=(sinx)平方-根号3sin(pai+x)*cosx
求定积分上限pai/2下限pai/3 4sin^2x/(1-cosx)dx的值
f(x)=根号3cosx+sinx(-pai/2
解sinx=2sin(pai/3-x)