(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了

(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了 [log2(3)+log4(9)][log3(4)+log9(2)]等于 (log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7) 1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 (log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32 log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2 log2 根号2+log9 27+4^log4 13=? log2^根号下2+log9^27+4^(log4^13) (log3^2 + log9^4)×(log4^3 + log8^3) (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 若log2^3×log3^4×log4^x=log9^3 ,求x （log2 3+log4 27）*（log3 4+log9 8）=