sin14/3π+cos(-23π/4)+tan(-25π/3)=?
sin14/3π+cos(-23π/4)+tan(-25π/3)=?
求值:sin14π3+cos(−25π4)
已知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^
知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^2
已知tan(α+π/4)=3,求cosα+2sinα/cosα-sinα的值
sin(-4π/3)cos(-23π/6)tan(25π/4)=?
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
tan(π/4+θ)=3 ,求sin2θ - 2*(cosθ)^2
SIN(-7/6π),cos(15/4π),tan(-8/3π),tan(33/4π)
已知tan(π-α)=2,求sin²α-2sinαcosα-cos²α/4cos²α-3s
已知tan(π-α)=2,求sinα-2sinαcosα-cosα/4cosα-3sinα的值
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan