急!a^x a^y = a^x [1 a^(y-x)] return countTable[v]
急!a^x a^y = a^x [1 a^(y-x)] return countTable[v]
a^x a^y = a^x [1 a^(y-x)] return countTable[v]
a^y = a^x [1 a^(y-x)] return countTable[v]
说说f(x)=1/√3(x^2-3x 2)return countTable[v]
ReturnType a(byte x,double y){return (short)x/y*2;} A byte B
int func(int x,int y ) { return(x+y) } main() {int a=1,b=2,c
f(x)=2-(x分之3)return countTable[v]
求助f(x)=2-(x分之3)return countTable[v]
跪求f(x)=2-(x分之3)return countTable[v]
求导y=x^a+a^x+a^a
y=a^x+x^a+a^a求导
条件语句:(1)a=(x>y)?x:y; →if(x>y) a=x;else a=y;