作业帮A bullet of mass m traveling at velocity v strikes a lock of
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A bullet of mass m traveling at velocity v strikes a lock of mass 2m that is attached to a rod of length R.The bellet collides with the block at a right angle and gets stuck in the block.The rod is free to rotate.What is the centripetal acceleration of the block after the collision?
答案（1/9)v方/R
答案（1/9)v方/R
碰撞过程水平方向动量守恒.
mv=(m+2m)v1 v1=v/3
碰撞后二者合为一,质量为3m,速度为v/3
向心加速度为v1²/R=9v²/R
再问： 向心加速度怎么求？
再问： 向心加速度怎么求？
再答：
mv=(m+2m)v1 v1=v/3
碰撞后二者合为一,质量为3m,速度为v/3
向心加速度为v1²/R=9v²/R
再问： 向心加速度怎么求？
再问： 向心加速度怎么求？
再答：
A bullet of mass m traveling at velocity v strikes a lock of
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