char *s1="12345",*s2="1234"; printf("%d\n",strlen(strcpy(s1,
char *s1="12345",*s2="1234"; printf("%d\n",strlen(strcpy(s1,
设char*1=“12345”,s2=“1234”;执行语句printf(“%d\n”,strlen(strcpy(s1
main(){ char *s,*s1="Here";s=s1;while(*s1)s1++;printf("%d\n"
若有说明char s1[]=“the boy”,s2[]=“is headsome”;,则使用函数strcpy(s1,s
while循环条件是while(s1 = strstr(s1,s2)) {s1+=strlen(s2)},
#include void fun(char *w,int n){char t,*s1,*s2;s1=w;s2=w n-
fun(char *w,int n) { char t,*s1,*s2; s1=w; s2=w+n-1; while(s
main() { char s[]="stop\0\n\""; printf("%d\n",strlen(s)) }
main() {char *s1,*s2,m; s1=s2=(char*)malloc(sizeof(char)); *
下面函数的功能是 a(s1,s2) char s1[],s2[];{while(*s2++=*s1++)}
下面程序的运行结果是: char c[]="\t\v\\\0will\n" printf("%d",strlen);
C语言题目求解char[ ]="\t \chinese\ \girl\n" printf("%d",strlen(s))