x²+x-(a²-a) x²-5x+3 x²-2根号2x-3 3x²+
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/23 13:24:07
x²+x-(a²-a) x²-5x+3 x²-2根号2x-3 3x²+4xy-y²
分解因式x²+x-(a²-a) x²-5x+3 x²-2根号2x-3 3x²+4xy-y²
分解因式x²+x-(a²-a) x²-5x+3 x²-2根号2x-3 3x²+4xy-y²
x²+x-(a²-a)
=x^2+x-a^2+a
=x^2-a^2+(x+a)
=(x+a)(x-a)+(x+a)
=(x+a)(x-a+1)
x^2-5x+3
=x^2-5x+25/4+3-25/4
=(x-5/2)^2-13/4
=(x-5/2+√13/2)(x-5/2-√13/2)
=[x-(5+√13)/2][x-(5-√13)/2]
x^2-2√2x-3
=(x-√2)^2-(√2)^2-3 (配方法)
=(x-√2)^2-2-3
=(x-√2)^2-5
=(x-√2)^2-(√5)^2
=(x-√2+√5)(x-√2-√5) (平方差公式
3x^2+4xy-y^2
=3(x²+ xy×4/3 - y²×1/3)
=3[(x²+ 2×2/3 ×xy +4/9y²) - y^2/3- 4/9y²]
=3[(x+2/3y)² - 7/9 y²]
=3(x+2/3y +√7/3y)(x+2/3y - √7/3y)
=3[x+(2+√7)/3y][x+(2-√7)/3y]
=x^2+x-a^2+a
=x^2-a^2+(x+a)
=(x+a)(x-a)+(x+a)
=(x+a)(x-a+1)
x^2-5x+3
=x^2-5x+25/4+3-25/4
=(x-5/2)^2-13/4
=(x-5/2+√13/2)(x-5/2-√13/2)
=[x-(5+√13)/2][x-(5-√13)/2]
x^2-2√2x-3
=(x-√2)^2-(√2)^2-3 (配方法)
=(x-√2)^2-2-3
=(x-√2)^2-5
=(x-√2)^2-(√5)^2
=(x-√2+√5)(x-√2-√5) (平方差公式
3x^2+4xy-y^2
=3(x²+ xy×4/3 - y²×1/3)
=3[(x²+ 2×2/3 ×xy +4/9y²) - y^2/3- 4/9y²]
=3[(x+2/3y)² - 7/9 y²]
=3(x+2/3y +√7/3y)(x+2/3y - √7/3y)
=3[x+(2+√7)/3y][x+(2-√7)/3y]
x²+x-(a²-a) x²-5x+3 x²-2根号2x-3 3x²+
计算:[(-5+x)(-x-5)]² (x+3)²-(x+2)(x-1) (3x-a)(3x+a)(
(3x/x-1-x/x+1)×x²-1/x 其中x=根号2-2 先化简
已知集合A={x|-x²+2x+3>0},B={x|x-2
(2a+x)²-(a-x)² =(2a+x+a-x)(2a+x-a+x)第一步 =3a(a+2x)第
设集合A={x|3x-2-x²
设集合A={x|x²+3x+2
1.已知x=2-根号3,求(x-1分之1-2x+x²) -(x²-x分之根号x²-2x+1
解方程(根号3)*(x²-x)=(根号2)*(x²+x)
已知x=根号3+1求根号(x²/1+2x+x²)
根号x²-2x+1(x
f(x)=x²+3x|x-2|