作业帮化简三角函数[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-p
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/16 10:15:56
化简三角函数[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-pi)]
[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-pi)]
算出来最后等于1 ,
[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-pi)]
算出来最后等于1 ,
[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-pi)]
=[(-sin(α))*(-cos(α))*cos(α)]/[tan(α)*(-cos^3(α))]
=-sinα*cosα*cosα*cosα/sinα*cosα*cosα*cosα
=-1
应该是-1
=[(-sin(α))*(-cos(α))*cos(α)]/[tan(α)*(-cos^3(α))]
=-sinα*cosα*cosα*cosα/sinα*cosα*cosα*cosα
=-1
应该是-1
化简三角函数[sin(α+pi)*cos(pi+α)*cos(α+2pi)]/[tan(pi+α)*cos^3(-α-p
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