SAT数学题……A positive integer is said to be "tir-factorable"if

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SAT数学题……
A positive integer is said to be "tir-factorable"if it is the product of three consecutive integers.How many positive integers less than 1000 are thr-factorable?
翻译一下的话是：
如果一个正整数是三个连续的整数的积的话,它就能被称做“tir-factorable”.（我不知道这个用中文怎么说,大概是表示可以因式分解为三个质数的）
那么有多少这种小于1000的正整数可以被称为“tir-factorable”?
晕啊……做英语题做多了脑子都不好使了~
ORZ……
都是那个三倍可因式分解的惹得祸……完全复杂化了~
啊……我死蠢了~（撞豆腐去……）

1000=10*10*10然后试一下9*10*11=990仍然满足,而10*11*12=1210就不满足了.
再找最小的,那就是6咯.6=1*2*3.
由于数目比较小,你完全可以将所有的符合的数列出来,这样就不容易晕了.
列出来是：
6=1*2*3
24=2*3*4
.
简化一下就是123,234,345,456,.,9、10、11
只看每组数的第一项就是1、2、3、4、5、6、7、8、9咯,也就是有9组数了呗,所以有九个.
PS：楼主的题目里面有关键词SAT,进来的人当然都懂英文,这个翻译以后就不必了吧.

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