求下列积分 1.∫(x+2倍根号x+3)/x dx 2.∫(x^2+sin^2x)/x^2sin^2x dx 3.∫co
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/29 09:39:19
求下列积分 1.∫(x+2倍根号x+3)/x dx 2.∫(x^2+sin^2x)/x^2sin^2x dx 3.∫cos^2(x/2) dx 谢啦,
1
∫(x+2√x+3)dx/x =∫dx+∫2dx/√x+∫3dx/x
=x+4√x+3lnx+C
2
∫(x^2+(sinx)^2)dx/[x^2(sinx)^2]
=∫dx/(sinx)^2+∫dx/x^2
=-cotx+(-1/x)+C
(cotx)'=-sinx/sinx-cosx^2/(sinx)^2=-(1+(cotx)^2)=-1/(sinx)^2
3
∫(cos(x/2))^2dx
=∫(1+cosx)dx/2
=x/2+sinx/2+C
∫(x+2√x+3)dx/x =∫dx+∫2dx/√x+∫3dx/x
=x+4√x+3lnx+C
2
∫(x^2+(sinx)^2)dx/[x^2(sinx)^2]
=∫dx/(sinx)^2+∫dx/x^2
=-cotx+(-1/x)+C
(cotx)'=-sinx/sinx-cosx^2/(sinx)^2=-(1+(cotx)^2)=-1/(sinx)^2
3
∫(cos(x/2))^2dx
=∫(1+cosx)dx/2
=x/2+sinx/2+C
求下列积分 1.∫(x+2倍根号x+3)/x dx 2.∫(x^2+sin^2x)/x^2sin^2x dx 3.∫co
求积分:∫sin^2 (x) /cos^3 (x) dx
用换元法求下列积分∫x^3sin^x/(x^4+1)dx∫x^3sin^2x/(x^4+1)dx
求下列不定积分:)积分号[(x^2+根号下x^3+3x)/根号下x]dx;2)积分号[sin(x/2)]^2dx;
∫sin(x) cos^2(x)dx
求积分 dx/(4+sin^2 (x))
求积分 sin(x^1/2) dx
∫sin^2 2x dx的积分怎么求
求∫e^sin(πx/2)dx的积分
求定积分 ∫[0,π]sin 2x dx
∫(x^3 )*(sin x^2) dx 求不定积分
求不定积分∫sin(x/2)dx